Einheiten Konverter

lbf*ft/(lb*°R) zu cal(IT)/g*°C

(Pound-Force-Fuß pro Pfund pro Grad Rankine zu Kalorien (IT) pro Gramm pro Celsius)

-10% Copy +10% -10% Copy +10%
=
⇄
lbf*ft/(lb*°R) zu J/kg*°C | lbf*ft/(lb*°R) zu J/(kg*K) | lbf*ft/(lb*°R) zu kgf*m/(kg*K) | lbf*ft/(lb*°R) zu J/g*°C | lbf*ft/(lb*°R) zu kJ/kg*K | lbf*ft/(lb*°R) zu kJ/kg*°C | lbf*ft/(lb*°R) zu Btu(IT)/(lb*°C) | lbf*ft/(lb*°R) zu cal(th)/g*°C | lbf*ft/(lb*°R) zu kcal(th)/kg*°C | lbf*ft/(lb*°R) zu kcal(th)/kg*K | lbf*ft/(lb*°R) zu Btu(th)/(lb*°F) | lbf*ft/(lb*°R) zu Btu(th)/(lb*°R) | lbf*ft/(lb*°R) zu cal(IT)/g*°C | lbf*ft/(lb*°R) zu cal(IT)/g°F | lbf*ft/(lb*°R) zu kcal(IT)/kg*°C | lbf*ft/(lb*°R) zu kcal(IT)/(kg*K) | lbf*ft/(lb*°R) zu Btu(IT)/lb*°F | lbf*ft/(lb*°R) zu Btu(IT)/(lb*°R) | lbf*ft/(lb*°R) zu CHU/(lb*°C)
👎
👍
Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 lbf*ft/(lb*°R)ist äquivalent zu 0.0013 cal(IT)/g*°C
Formel verwendet
1 Joule pro Kilogramm pro K = 0.185862535177479 Pound-Force-Fuß pro Pfund pro Grad Rankine
1 Joule pro Kilogramm pro K = 0.0002388458966275 Kalorien (IT) pro Gramm pro Celsius
∴ 1 Pound-Force-Fuß pro Pfund pro Grad Rankine = 0.00128506746343166 Kalorien (IT) pro Gramm pro Celsius

Andere lbf*ft/(lb*°R) Konvertierungen

© 2016-2024. A softUsvista venture!


Share Image
Let Others Know
✖
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!