Einheiten Konverter

cal(th)/g*°C zu lbf*ft/(lb*°R)

(Kalorien (th) pro Gramm pro Celsius zu Pound-Force-Fuß pro Pfund pro Grad Rankine)

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cal(th)/g*°C zu J/kg*°C | cal(th)/g*°C zu J/(kg*K) | cal(th)/g*°C zu lbf*ft/(lb*°R) | cal(th)/g*°C zu kgf*m/(kg*K) | cal(th)/g*°C zu J/g*°C | cal(th)/g*°C zu kJ/kg*K | cal(th)/g*°C zu kJ/kg*°C | cal(th)/g*°C zu Btu(IT)/(lb*°C) | cal(th)/g*°C zu kcal(th)/kg*°C | cal(th)/g*°C zu kcal(th)/kg*K | cal(th)/g*°C zu Btu(th)/(lb*°F) | cal(th)/g*°C zu Btu(th)/(lb*°R) | cal(th)/g*°C zu cal(IT)/g*°C | cal(th)/g*°C zu cal(IT)/g°F | cal(th)/g*°C zu kcal(IT)/kg*°C | cal(th)/g*°C zu kcal(IT)/(kg*K) | cal(th)/g*°C zu Btu(IT)/lb*°F | cal(th)/g*°C zu Btu(IT)/(lb*°R) | cal(th)/g*°C zu CHU/(lb*°C)
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2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 cal(th)/g*°Cist äquivalent zu 777.6488 lbf*ft/(lb*°R)
Formel verwendet
1 Joule pro Kilogramm pro K = 0.0002390057361377 Kalorien (th) pro Gramm pro Celsius
1 Joule pro Kilogramm pro K = 0.185862535177479 Pound-Force-Fuß pro Pfund pro Grad Rankine
∴ 1 Kalorien (th) pro Gramm pro Celsius = 777.648847182466 Pound-Force-Fuß pro Pfund pro Grad Rankine

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