Einheiten Konverter

Btu(IT)/(lb*°R) zu cal(th)/g*°C

(Btu (IT) pro Pfund pro Grad Rankine zu Kalorien (th) pro Gramm pro Celsius)

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Btu(IT)/(lb*°R) zu J/kg*°C | Btu(IT)/(lb*°R) zu J/(kg*K) | Btu(IT)/(lb*°R) zu lbf*ft/(lb*°R) | Btu(IT)/(lb*°R) zu kgf*m/(kg*K) | Btu(IT)/(lb*°R) zu J/g*°C | Btu(IT)/(lb*°R) zu kJ/kg*K | Btu(IT)/(lb*°R) zu kJ/kg*°C | Btu(IT)/(lb*°R) zu Btu(IT)/(lb*°C) | Btu(IT)/(lb*°R) zu cal(th)/g*°C | Btu(IT)/(lb*°R) zu kcal(th)/kg*°C | Btu(IT)/(lb*°R) zu kcal(th)/kg*K | Btu(IT)/(lb*°R) zu Btu(th)/(lb*°F) | Btu(IT)/(lb*°R) zu Btu(th)/(lb*°R) | Btu(IT)/(lb*°R) zu cal(IT)/g*°C | Btu(IT)/(lb*°R) zu cal(IT)/g°F | Btu(IT)/(lb*°R) zu kcal(IT)/kg*°C | Btu(IT)/(lb*°R) zu kcal(IT)/(kg*K) | Btu(IT)/(lb*°R) zu Btu(IT)/lb*°F | Btu(IT)/(lb*°R) zu CHU/(lb*°C)
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2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 Btu(IT)/(lb*°R)ist äquivalent zu 1.0007 cal(th)/g*°C
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000238845896632776 Btu (IT) pro Pfund pro Grad Rankine
1 Joule pro Kilogramm pro K = 0.0002390057361377 Kalorien (th) pro Gramm pro Celsius
∴ 1 Btu (IT) pro Pfund pro Grad Rankine = 1.0006692160392 Kalorien (th) pro Gramm pro Celsius

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