Einheiten Konverter

Btu(IT)/(lb*°R) zu lbf*ft/(lb*°R)

(Btu (IT) pro Pfund pro Grad Rankine zu Pound-Force-Fuß pro Pfund pro Grad Rankine)

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Btu(IT)/(lb*°R) zu J/kg*°C | Btu(IT)/(lb*°R) zu J/(kg*K) | Btu(IT)/(lb*°R) zu lbf*ft/(lb*°R) | Btu(IT)/(lb*°R) zu kgf*m/(kg*K) | Btu(IT)/(lb*°R) zu J/g*°C | Btu(IT)/(lb*°R) zu kJ/kg*K | Btu(IT)/(lb*°R) zu kJ/kg*°C | Btu(IT)/(lb*°R) zu Btu(IT)/(lb*°C) | Btu(IT)/(lb*°R) zu cal(th)/g*°C | Btu(IT)/(lb*°R) zu kcal(th)/kg*°C | Btu(IT)/(lb*°R) zu kcal(th)/kg*K | Btu(IT)/(lb*°R) zu Btu(th)/(lb*°F) | Btu(IT)/(lb*°R) zu Btu(th)/(lb*°R) | Btu(IT)/(lb*°R) zu cal(IT)/g*°C | Btu(IT)/(lb*°R) zu cal(IT)/g°F | Btu(IT)/(lb*°R) zu kcal(IT)/kg*°C | Btu(IT)/(lb*°R) zu kcal(IT)/(kg*K) | Btu(IT)/(lb*°R) zu Btu(IT)/lb*°F | Btu(IT)/(lb*°R) zu CHU/(lb*°C)
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2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 Btu(IT)/(lb*°R)ist äquivalent zu 778.1693 lbf*ft/(lb*°R)
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000238845896632776 Btu (IT) pro Pfund pro Grad Rankine
1 Joule pro Kilogramm pro K = 0.185862535177479 Pound-Force-Fuß pro Pfund pro Grad Rankine
∴ 1 Btu (IT) pro Pfund pro Grad Rankine = 778.169262263867 Pound-Force-Fuß pro Pfund pro Grad Rankine

Andere Btu(IT)/(lb*°R) Konvertierungen

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