Einheiten Konverter

cal(IT)/g°F zu Btu(th)/(lb*°F)

(Kalorien (IT) pro Gramm pro Grad Fahrenheit zu Btu (th) pro Pfund pro Grad Fahrenheit)

-10% Copy +10% -10% Copy +10%
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cal(IT)/g°F zu J/kg*°C | cal(IT)/g°F zu J/(kg*K) | cal(IT)/g°F zu lbf*ft/(lb*°R) | cal(IT)/g°F zu kgf*m/(kg*K) | cal(IT)/g°F zu J/g*°C | cal(IT)/g°F zu kJ/kg*K | cal(IT)/g°F zu kJ/kg*°C | cal(IT)/g°F zu Btu(IT)/(lb*°C) | cal(IT)/g°F zu cal(th)/g*°C | cal(IT)/g°F zu kcal(th)/kg*°C | cal(IT)/g°F zu kcal(th)/kg*K | cal(IT)/g°F zu Btu(th)/(lb*°F) | cal(IT)/g°F zu Btu(th)/(lb*°R) | cal(IT)/g°F zu cal(IT)/g*°C | cal(IT)/g°F zu kcal(IT)/kg*°C | cal(IT)/g°F zu kcal(IT)/(kg*K) | cal(IT)/g°F zu Btu(IT)/lb*°F | cal(IT)/g°F zu Btu(IT)/(lb*°R) | cal(IT)/g°F zu CHU/(lb*°C)
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Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 cal(IT)/g°Fist äquivalent zu 1.0007 Btu(th)/(lb*°F)
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000238845896627496 Kalorien (IT) pro Gramm pro Grad Fahrenheit
1 Joule pro Kilogramm pro K = 0.000239005796104515 Btu (th) pro Pfund pro Grad Fahrenheit
∴ 1 Kalorien (IT) pro Gramm pro Grad Fahrenheit = 1.00066946713038 Btu (th) pro Pfund pro Grad Fahrenheit

Andere cal(IT)/g°F Konvertierungen

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