Einheiten Konverter

Btu(IT)/lb*°F zu cal(IT)/g°F

(Btu (IT) pro Pfund pro Grad Fahrenheit zu Kalorien (IT) pro Gramm pro Grad Fahrenheit)

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Btu(IT)/lb*°F zu J/kg*°C | Btu(IT)/lb*°F zu J/(kg*K) | Btu(IT)/lb*°F zu lbf*ft/(lb*°R) | Btu(IT)/lb*°F zu kgf*m/(kg*K) | Btu(IT)/lb*°F zu J/g*°C | Btu(IT)/lb*°F zu kJ/kg*K | Btu(IT)/lb*°F zu kJ/kg*°C | Btu(IT)/lb*°F zu Btu(IT)/(lb*°C) | Btu(IT)/lb*°F zu cal(th)/g*°C | Btu(IT)/lb*°F zu kcal(th)/kg*°C | Btu(IT)/lb*°F zu kcal(th)/kg*K | Btu(IT)/lb*°F zu Btu(th)/(lb*°F) | Btu(IT)/lb*°F zu Btu(th)/(lb*°R) | Btu(IT)/lb*°F zu cal(IT)/g*°C | Btu(IT)/lb*°F zu cal(IT)/g°F | Btu(IT)/lb*°F zu kcal(IT)/kg*°C | Btu(IT)/lb*°F zu kcal(IT)/(kg*K) | Btu(IT)/lb*°F zu Btu(IT)/(lb*°R) | Btu(IT)/lb*°F zu CHU/(lb*°C)
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Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 Btu(IT)/lb*°Fist äquivalent zu 1 cal(IT)/g°F
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000238845896632776 Btu (IT) pro Pfund pro Grad Fahrenheit
1 Joule pro Kilogramm pro K = 0.000238845896627496 Kalorien (IT) pro Gramm pro Grad Fahrenheit
∴ 1 Btu (IT) pro Pfund pro Grad Fahrenheit = 0.999999999977895 Kalorien (IT) pro Gramm pro Grad Fahrenheit

Andere Btu(IT)/lb*°F Konvertierungen

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