Einheiten Konverter

kcal(IT)/(kg*K) zu Btu(IT)/lb*°F

(Kilokalorie (IT) pro Kilogramm pro K zu Btu (IT) pro Pfund pro Grad Fahrenheit)

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kcal(IT)/(kg*K) zu J/kg*°C | kcal(IT)/(kg*K) zu J/(kg*K) | kcal(IT)/(kg*K) zu lbf*ft/(lb*°R) | kcal(IT)/(kg*K) zu kgf*m/(kg*K) | kcal(IT)/(kg*K) zu J/g*°C | kcal(IT)/(kg*K) zu kJ/kg*K | kcal(IT)/(kg*K) zu kJ/kg*°C | kcal(IT)/(kg*K) zu Btu(IT)/(lb*°C) | kcal(IT)/(kg*K) zu cal(th)/g*°C | kcal(IT)/(kg*K) zu kcal(th)/kg*°C | kcal(IT)/(kg*K) zu kcal(th)/kg*K | kcal(IT)/(kg*K) zu Btu(th)/(lb*°F) | kcal(IT)/(kg*K) zu Btu(th)/(lb*°R) | kcal(IT)/(kg*K) zu cal(IT)/g*°C | kcal(IT)/(kg*K) zu cal(IT)/g°F | kcal(IT)/(kg*K) zu kcal(IT)/kg*°C | kcal(IT)/(kg*K) zu Btu(IT)/lb*°F | kcal(IT)/(kg*K) zu Btu(IT)/(lb*°R) | kcal(IT)/(kg*K) zu CHU/(lb*°C)
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2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 kcal(IT)/(kg*K)ist äquivalent zu 1 Btu(IT)/lb*°F
Formel verwendet
1 Joule pro Kilogramm pro K = 0.0002388458966275 Kilokalorie (IT) pro Kilogramm pro K
1 Joule pro Kilogramm pro K = 0.000238845896632776 Btu (IT) pro Pfund pro Grad Fahrenheit
∴ 1 Kilokalorie (IT) pro Kilogramm pro K = 1.00000000002209 Btu (IT) pro Pfund pro Grad Fahrenheit

Andere kcal(IT)/(kg*K) Konvertierungen

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