Einheiten Konverter

kgf*m/(kg*K) zu cal(IT)/g°F

(Kilogram-Force Meter pro Kilogramm pro Kelvin zu Kalorien (IT) pro Gramm pro Grad Fahrenheit)

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kgf*m/(kg*K) zu J/kg*°C | kgf*m/(kg*K) zu J/(kg*K) | kgf*m/(kg*K) zu lbf*ft/(lb*°R) | kgf*m/(kg*K) zu J/g*°C | kgf*m/(kg*K) zu kJ/kg*K | kgf*m/(kg*K) zu kJ/kg*°C | kgf*m/(kg*K) zu Btu(IT)/(lb*°C) | kgf*m/(kg*K) zu cal(th)/g*°C | kgf*m/(kg*K) zu kcal(th)/kg*°C | kgf*m/(kg*K) zu kcal(th)/kg*K | kgf*m/(kg*K) zu Btu(th)/(lb*°F) | kgf*m/(kg*K) zu Btu(th)/(lb*°R) | kgf*m/(kg*K) zu cal(IT)/g*°C | kgf*m/(kg*K) zu cal(IT)/g°F | kgf*m/(kg*K) zu kcal(IT)/kg*°C | kgf*m/(kg*K) zu kcal(IT)/(kg*K) | kgf*m/(kg*K) zu Btu(IT)/lb*°F | kgf*m/(kg*K) zu Btu(IT)/(lb*°R) | kgf*m/(kg*K) zu CHU/(lb*°C)
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2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 kgf*m/(kg*K)ist äquivalent zu 0.0023 cal(IT)/g°F
Formel verwendet
1 Joule pro Kilogramm pro K = 0.1019716212978 Kilogram-Force Meter pro Kilogramm pro Kelvin
1 Joule pro Kilogramm pro K = 0.000238845896627496 Kalorien (IT) pro Gramm pro Grad Fahrenheit
∴ 1 Kilogram-Force Meter pro Kilogramm pro Kelvin = 0.00234227811216187 Kalorien (IT) pro Gramm pro Grad Fahrenheit

Andere kgf*m/(kg*K) Konvertierungen

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